(2x^2-2x-12)/(x^2-x-6)=0

Simple and best practice solution for (2x^2-2x-12)/(x^2-x-6)=0 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for (2x^2-2x-12)/(x^2-x-6)=0 equation: 


D( x )

x^2-x-6 = 0

x^2-x-6 = 0

x^2-x-6 = 0

x^2-x-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+1)/(1*2) or x = (1-25^(1/2))/(1*2)

x = 3 or x = -2

x in (-oo:-2) U (-2:3) U (3:+oo)

(2*x^2-(2*x)-12)/(x^2-x-6) = 0

(2*x^2-2*x-12)/(x^2-x-6) = 0

2*x^2-2*x-12 = 0

2*(x^2-x-6) = 0

x^2-x-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+1)/(1*2) or x = (1-25^(1/2))/(1*2)

x = 3 or x = -2

2*(x+2)*(x-3) = 0

x^2-x-6 = 0

x^2-x-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+1)/(1*2) or x = (1-25^(1/2))/(1*2)

x = 3 or x = -2

(x+2)*(x-3) = 0

(2*(x+2)*(x-3))/((x+2)*(x-3)) = 0

( 2 )

2 = 0

x belongs to the empty set

( x+2 )

x+2 = 0 // - 2

x = -2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -2} 

x in { 3} 

x belongs to the empty set

See similar equations:

| a=p(a+rt) | | 3x+7=7x-27 | | x+6-10x=-20 | | 10+1.50x=12.50+1.00x | | 1-28+p=7(p-10) | | (d+3)/4=2 | | x^3+27x^3=0 | | 32-6*2+5= | | 32-6.2+5= | | 1(5a+6)=2(3+8) | | 1/8-1/16 | | 2x-48=33 | | 404=7y+10(20-y) | | 4-(x+6)=5x-8 | | -32-4x=-2(-4x+6)-7x | | -(8s+3)-(s+5)= | | -1-28+p=7(p-10) | | 404=10z+7(20-z) | | 4.6+2=3.6 | | 9(3x+1)=4x-9x | | -(5a+6)=2(39+8) | | 41x-24-7x=12+34x-36 | | 5x-40-x+6=18 | | 10x-1=-31 | | 25÷1/5= | | -0.1x+2.11=-0.5x+6.11 | | 14+4x=6(x+4) | | x-1+2x-14=9 | | 0.43x+0.71(140-x)=0.65(140) | | -3(5s-2)-6=-2(9x+1)-2 | | 3x-4+2x=12 | | -1(1+7x)-6(-7-x)=26 |

Equations solver categories